diff options
Diffstat (limited to 'examples/breakout/client.rs')
| -rw-r--r-- | examples/breakout/client.rs | 15 |
1 files changed, 11 insertions, 4 deletions
diff --git a/examples/breakout/client.rs b/examples/breakout/client.rs index ff55257..a7b549b 100644 --- a/examples/breakout/client.rs +++ b/examples/breakout/client.rs @@ -363,14 +363,19 @@ pub(crate) fn setup_breakout(mut commands: Commands, asset_server: Res<AssetServ let total_width_of_bricks = (RIGHT_WALL - LEFT_WALL) - 2. * GAP_BETWEEN_BRICKS_AND_SIDES; let bottom_edge_of_bricks = BOTTOM_WALL + GAP_BETWEEN_PADDLE_AND_FLOOR + GAP_BETWEEN_PADDLE_AND_BRICKS; - let total_height_of_bricks = TOP_WALL - bottom_edge_of_bricks - GAP_BETWEEN_BRICKS_AND_CEILING; + let available_height_for_bricks = TOP_WALL + - bottom_edge_of_bricks + - (GAP_BETWEEN_PADDLE_AND_FLOOR + GAP_BETWEEN_PADDLE_AND_BRICKS); assert!(total_width_of_bricks > 0.0); - assert!(total_height_of_bricks > 0.0); + assert!(available_height_for_bricks > 0.0); // Given the space available, compute how many rows and columns of bricks we can fit let n_columns = (total_width_of_bricks / (BRICK_SIZE.x + GAP_BETWEEN_BRICKS)).floor() as usize; - let n_rows = (total_height_of_bricks / (BRICK_SIZE.y + GAP_BETWEEN_BRICKS)).floor() as usize; + let n_rows = + (available_height_for_bricks / (BRICK_SIZE.y + GAP_BETWEEN_BRICKS)).floor() as usize; + let height_occupied_by_bricks = + n_rows as f32 * (BRICK_SIZE.y + GAP_BETWEEN_BRICKS) - GAP_BETWEEN_BRICKS; let n_vertical_gaps = n_columns - 1; // Because we need to round the number of columns, @@ -385,7 +390,9 @@ pub(crate) fn setup_breakout(mut commands: Commands, asset_server: Res<AssetServ // In Bevy, the `translation` of an entity describes the center point, // not its bottom-left corner let offset_x = left_edge_of_bricks + BRICK_SIZE.x / 2.; - let offset_y = bottom_edge_of_bricks + BRICK_SIZE.y / 2.; + let offset_y = bottom_edge_of_bricks + + BRICK_SIZE.y / 2. + + (available_height_for_bricks - height_occupied_by_bricks) / 2.; // Offset so that both players are at an equal distance of the bricks for row in 0..n_rows { for column in 0..n_columns { |